ln(2n^2+1)-ln(n^2+1)=0.7

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Solution for ln(2n^2+1)-ln(n^2+1)=0.7 equation: 


Simplifying
ln(2n2 + 1) + -1ln(n2 + 1) = 0.7

Reorder the terms:
ln(1 + 2n2) + -1ln(n2 + 1) = 0.7
(1 * ln + 2n2 * ln) + -1ln(n2 + 1) = 0.7
(1ln + 2ln3) + -1ln(n2 + 1) = 0.7

Reorder the terms:
1ln + 2ln3 + -1ln(1 + n2) = 0.7
1ln + 2ln3 + (1 * -1ln + n2 * -1ln) = 0.7
1ln + 2ln3 + (-1ln + -1ln3) = 0.7

Reorder the terms:
1ln + -1ln + 2ln3 + -1ln3 = 0.7

Combine like terms: 1ln + -1ln = 0
0 + 2ln3 + -1ln3 = 0.7
2ln3 + -1ln3 = 0.7

Combine like terms: 2ln3 + -1ln3 = 1ln3
1ln3 = 0.7

Solving
1ln3 = 0.7

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '1n3'.
l = 0.7n-3

Simplifying
l = 0.7n-3

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